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Help with how to solve this!!

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Help with how to solve this!!

Unread postby randall weidner » 19 Apr 2015, 00:30

Can someone help me with this problem I am having I keep getting an error message and don't know what I am doing wrong. Here is a screen shot of the problem.
Thank you in advance.

Chap 2 problem.jpg
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Last edited by Excale on 19 Apr 2015, 00:58, edited 1 time in total.
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Re: Help with how to solve this!!

Unread postby Levak » 19 Apr 2015, 00:54

Put the square after the parenthesis.
Indeed, tan, sin and cos are functions, which means they need the opening parenthesis to follow by the function name.

In other words, instead of doing tan^2(120), do tan(120)^2, and same for others.
Last edited by Bisam on 19 Apr 2015, 01:13, edited 1 time in total.
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Re: Help with how to solve this!!

Unread postby randall weidner » 19 Apr 2015, 02:22

I tried that and it gave me an answer of 45/4 and the correct answer I found out was 51/4 but I still don't know how to get to that answer.
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Re: Help with how to solve this!!

Unread postby Bisam » 19 Apr 2015, 09:28

You "correct" answer is wrong !
$mathjax$\cos(90°)=0$mathjax$
,
$mathjax$\sin(150°)=\frac{1}{2}$mathjax$
and
$mathjax$\tan(120°)=-\sqrt{3}$mathjax$

Hence,
$mathjax$4\tan^2(120°)-3\sin^2(150°)-\cos^2(90°)=4\times 3-3\times\frac{1}{4}-0=\frac{48-3}{4}=\frac{45}{4}$mathjax$
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