Soit n>0 (on a déjà S(0) de toute façon).
On a S(n)=S(n)-S(0)=sum(k=0..n-1,S(k+1)-S(k))=sum(k=0..n-1,(k+1)p)=sum(k=0..n,kp).
Faulhaber, le retour
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Re: Faulhaber, le retour
by Hayleia » 06 Feb 2014, 19:59
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