tutorial 1b,
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Catégorie :Category: nCreator TI-Nspire
Auteur Author: oONOLTZOo
Type : Classeur 3.0.1
Page(s) : 1
Taille Size: 1.80 Ko KB
Mis en ligne Uploaded: 10/10/2024 - 08:17:25
Uploadeur Uploader: oONOLTZOo (Profil)
Téléchargements Downloads: 1
Visibilité Visibility: Archive publique
Shortlink : http://ti-pla.net/a4245219
Type : Classeur 3.0.1
Page(s) : 1
Taille Size: 1.80 Ko KB
Mis en ligne Uploaded: 10/10/2024 - 08:17:25
Uploadeur Uploader: oONOLTZOo (Profil)
Téléchargements Downloads: 1
Visibilité Visibility: Archive publique
Shortlink : http://ti-pla.net/a4245219
Description
Fichier Nspire généré sur TI-Planet.org.
Compatible OS 3.0 et ultérieurs.
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Referring to Al-Si phase diagram shown in figure 2,explain why Al-Si with 10 wt. % of silicon cannot be heat-treated by precipitation hardening? (Hint: predict the microstructure of the alloy using the phase diagram, and explain your answerfrom there). For the Al-Si alloy with 10 wt. % silicon , referring to the Al-Si phasediagram: Microstructure : According to the phase diagram, an Al-Si alloy with 10 wt. % Si solidifies into a eutectic structure composed of primary ±-Al and Si phases. This structure is typical of hypoeutectic alloys (compositions below the eutectic point, which is around 12.6 wt. % Si). Precipitation Hardening : Precipitation hardening requires a phase transformation where a solid solution decomposes into fine precipitates of a second phase upon aging. However, in the case of Al-Si alloys, the microstructure already contains large, stable Si particles. These Si particles are not formed through precipitation from a solid solution; they exist as part of the as-cast microstructure. Because the alloy with 10 wt. % Si does not have asupersaturated solid solution capable of forming fine precipitates upon aging, precipitationhardening is not possible . The silicon is already present as a second phaseand will not precipitate out from the aluminum matrix during heat treatment.Therefore, the alloy cannot be strengthened by this method. Made with nCreator - tiplanet.org
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Compatible OS 3.0 et ultérieurs.
<<
Referring to Al-Si phase diagram shown in figure 2,explain why Al-Si with 10 wt. % of silicon cannot be heat-treated by precipitation hardening? (Hint: predict the microstructure of the alloy using the phase diagram, and explain your answerfrom there). For the Al-Si alloy with 10 wt. % silicon , referring to the Al-Si phasediagram: Microstructure : According to the phase diagram, an Al-Si alloy with 10 wt. % Si solidifies into a eutectic structure composed of primary ±-Al and Si phases. This structure is typical of hypoeutectic alloys (compositions below the eutectic point, which is around 12.6 wt. % Si). Precipitation Hardening : Precipitation hardening requires a phase transformation where a solid solution decomposes into fine precipitates of a second phase upon aging. However, in the case of Al-Si alloys, the microstructure already contains large, stable Si particles. These Si particles are not formed through precipitation from a solid solution; they exist as part of the as-cast microstructure. Because the alloy with 10 wt. % Si does not have asupersaturated solid solution capable of forming fine precipitates upon aging, precipitationhardening is not possible . The silicon is already present as a second phaseand will not precipitate out from the aluminum matrix during heat treatment.Therefore, the alloy cannot be strengthened by this method. Made with nCreator - tiplanet.org
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