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Practice Exam and Prac 1


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Catégorie :Category: nCreator TI-Nspire
Auteur Author: minisavage
Type : Classeur 3.0.1
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Mis en ligne Uploaded: 13/11/2024 - 06:57:35
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Shortlink : http://ti-pla.net/a4313806

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Fichier Nspire généré sur TI-Planet.org.

Compatible OS 3.0 et ultérieurs.

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E Ò trans Z Ò cis Which bond is the weakest: Lowest BDE What is correct about reaction rates: Nothing to do with ”H but as Rate ‘ Ea “ Carboanions may be stabilized by Inductive effects and Resonance Carbon-carbon double bonds are shorter and stronger than carbon-carbon single bonds Greater surface area Ò stronger BDE Ò higher boiling point   Use words to explain why Ã bonds are stronger than À bonds: With Ã bonds, the majority of e density is directly between the nucli, pulling them tighter and shielding them With À bonds, the majority of e density is above and below the plane of the nuclei, not pulling/shielding as much. No pi bonds or lone pair = no resonance Inductive effects: alkyl groups are weak e donors, stabilizing carbocations by inductive effects. Br is e withdrawing, destabalizing carbocations (least stable) Hyperconjugation: more adjacent alkyl groups lead to more hyperconjugation (overlap) Rank the alkenes in order of increasing stability Inductive effects: The more e donating alkyl groups, the more stable the À bonds Steric effects: The greater the distance between bulky groups, the more stable monosubstitued: least stable | disubstituted (depends on bond angles steric effects) Values of ”G and Keq denote a reaction that favors the reactants  - ”G > 0, Bad < 1 Which statement about Keq is correct for an endergonic reaction at equilibrium  - Bad < 1 An exergonic reaction has which thermodynamic values?  - Keq > 1 and ”G < 0 Which values contribute to an exergonic reaction  - -”H and +”S Which step in a radical halogenation reaction does not have a radical as a product  - Termination Which step in the radical chlorination of methane requires light energy?  - Initiation Which reaction favors the formation of the products?  - One that is spontaneous Which step in the radical chlorination of methane has two radicals as products?  - Initiation Which step in the radical monochlorination of methane involves the homolytic cleavage of a carbon-hydrogen single bond  - first propagation Which type of process is taking place in the reaction shown below? (CH3)3CBrÒ(CH3)3C+ + Br-  - Heterolytic bond cleavage Which statement about carbon radicals is correct  - They are neither nucleophiles nor electrophiles Which is a progagtion step in the reaction of Cl2 and ethane in the presence of light  - Ch3C"H2 + Cl2 Ò CH3CH2CL + Cl Show mechanistically how dichloromethane is a potential product in the radical chlorination of methane  CH4 _ xs Cl2 Ò (Hv or ”) CH2Cl2 + many other products  - As this is a emchanisms question, you must show arrows indicating electron movement. The second chlorine is added in additional propagation steps. Made with nCreator - tiplanet.org
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